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Dissociation constant of NH(4)OH is 1.8 ...

Dissociation constant of `NH_(4)OH` is `1.8 xx 10^(-5)` . The hydrolysis constant of `NH_(4)Cl` would be

A

`1.80 xx 10^(-19)`

B

`5.55 xx 10^(-10)`

C

`5.55 xx 10^(-5)`

D

`1.80 xx 10^(-5)`

Text Solution

Verified by Experts

The correct Answer is:
B
`K_(h)=(K_(w))/(K_(b))=(10^(-14))/(1.8xx10^(-5))=5.55 xx 10^(-10)`
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