For preparing a buffer solution of `pH 6` by mixing sodium accetate and acetic, the ratio of the concentration of salt and acid should be `(K_(a)=10^(-5))`

Options

A. `1:10`
B. `10:1`
C. `100 :1`
D. `1:100`

Answer

B

Explanation

`pH=pK_(a)+log. (["Salt"])/(["base"])`
`pK_(a)=-log K_(a)=-log10^(-5)= +5`
`log.(["Salt"])/(["base"])=pH -pK_(a)=6-5=1`
`(["Salt"])/(["base"])=` antilog `(1)=10`
Thus [salt]`:`[base]`10:1`