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The dissociation constant of water is 1 ...

The dissociation constant of water is `1 xx 10^(-14) mol ^(-2) litre ^(-2)`. What is the pH of 0.001 M KOH soluiton ?

A

`10^(-11)`

B

`10^(-3)`

C

3

D

11

Text Solution

Verified by Experts

The correct Answer is:
D
`[OH^(-)]=[KOH]=0.001M =1xx10^(-3)M`
`:. p(OH)=-log (1xx 10^-3))=3`
`pH=14-p(OH)=14-3=11`
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