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Solution of 0.1 N NH(4)OH and 0.1 N NH(4...

Solution of `0.1 N NH_(4)OH` and `0.1 N NH_(4)Cl` has `pH 9.25`, then find out `K_(b)` of `NH_(4)OH`.

A

9.25

B

4.75

C

3.75

D

8.25

Text Solution

Verified by Experts

The correct Answer is:
B
As `[NH_(4)Cl]=[NH_(4)OH],pOH=pK_(b)`.
`:. pK_(b)=pOH =14-pH=14-9.25=4.75`
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