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A solution of an acid has pH= 4.70. Find...

A solution of an acid has `pH= 4.70`. Find out the concentration of `OH^(-)` ions `(pK_(w)=14)`.

A

`5 xx 10^(-10)`

B

`4 xx 10^(-10)`

C

`2 xx 10^(-5)`

D

`9 xx 10^(-4)`

Text Solution

Verified by Experts

The correct Answer is:
A
`pH=4.70 implies -log [H^(+)]=4.70`
`:. log[H^(+)]=-4.7 =bar(5).30`
or `[H^(+)]=1.999xx10^(-5)~~2 xx 10^(-5)`
`pK_(w)=14 implies [H^(+)]xx[OH^(-)]=10^(-14)`
`:. [OH^(-)]=(10^(-14))/(2 xx 10^(-5))=0.5 xx 10^(-9) = 5 xx 10^(-10)`
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