The value of ionic product of water at 393K is

Options

A. less than `1 xx 10^(-14)`
B. greater than `1 xx 10^(-14)`
C. equal to `1 xx 10^(-14)`
D. equal to `1 xx 10^(-7)`

Explanation

To find the value of the ionic product of water (Kw) at 393 K, we can follow these steps:

### Step 1: Understand the Ionic Product of Water
The ionic product of water (Kw) is defined as the product of the concentrations of hydrogen ions [H⁺] and hydroxide ions [OH⁻] in water at a given temperature. At 25°C (298 K), Kw is known to be 1 x 10⁻¹⁴.

### Step 2: Recognize the Effect of Temperature on Kw
The ionic product of water increases with an increase in temperature. This is because higher temperatures provide more energy for the dissociation of water molecules into H⁺ and OH⁻ ions.

### Step 3: Compare Temperatures
Since we are looking for Kw at 393 K, we note that this temperature is significantly higher than 298 K.

### Step 4: Predict the Change in Kw
As the temperature increases from 298 K to 393 K, the dissociation of water will increase, leading to a higher concentration of H⁺ and OH⁻ ions. Therefore, we can conclude that Kw at 393 K will be greater than 1 x 10⁻¹⁴.

### Step 5: Conclusion
Thus, the value of the ionic product of water at 393 K is greater than 1 x 10⁻¹⁴.

### Final Answer
Kw at 393 K > 1 x 10⁻¹⁴.

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