The solubility product of a sparingly soluble salt `AX_(2)` is `3.2xx10^(-11)`. Its solubility (in `mo//L`) is

Options

A. `4 xx 10^(-4)`
B. `5.6 xx 10^(-6)`
C. `3.1 xx 10^(-4)`
D. `2 xx 10^(-4)`

Answer

D

Explanation

`AX_(3)hArr underset(s)(A^(2+))+underset(2s)(2X^(-))`
`K_(sp)=[A^(2+)][X^(-)]^(2)`
`3.2xx 10^(-11)=s(2s)^(2)`
`4s^(3)=3.2 xx 10^(-11)`
`s^(3)=8 xx 10^(-12)`
`s=2 xx 10^(-4) mol L^(-1)`