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At 90^(@)C, pure water has [H(3)O^(o+)] ...

At `90^(@)C`, pure water has `[H_(3)O^(o+)] = 10^(-6)M`. What is the value of `K_(w)` at `90^(@)C`

A

`10^(-6)`

B

`10^(-8)`

C

`10^(-12)`

D

`10^(14)`

Text Solution

Verified by Experts

The correct Answer is:
C
In pure waer,
`[OH^(-)]=[H_(3)O^(+)]=10^(-6) mol L^(-1)`
`K_(w)=[OH^(-)][H_(3)O^(+)]=10^(-6)xx 10^(-6) =10^(-12)`
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