The solubility product of a salt having general formula `MX_(2)` in water is `4xx10^(-12)`. The concentration of `M^(2+) ions` in the aqueous solution of the salt is:

Options

A. `2.0 xx 10^(-6) M`
B. `1.0 xx 10^(-4)M`
C. `1.6 xx 10^(-4)M`
D. `4.0 xx 10^(-10) M`

Answer

B

Explanation

`MX_(2)(s) overset(aq) (hArr)M^(2+)t2X^(-)`
`K_(sp)=[M^(2+)][X^(-)]`
Let `[M^(2+)] =x " ":. [X^(-)]=2x`
`K_(sp)=[M^(2+)][X^(-)]^(2)`
`4 xx 10^(-12)=x ( 2x)^(2)`
`4 xx 10^(-12) =4x^(3)`
` x=10^(-4)M`