The precipitate of `Ag_(2)CrO_(4)(K_(sp))=1.1 xx 10^(-12)` is obtained when equal volumes of the following mixed

Options

A. `10^(-5) M Ag^(+) ` and `10^(-3) M CrO_(4)^(2-)`
B. `10^(-5) M Ag^(+)` and `10^(-2) M CrO_(4)^(2-)`
C. `10^(-4)M Ag^(+) ` and `10^(-2) M CrO_(4)^(2-)`
D. `10^(-7) M Ag^(+) ` and `10^(-3) CrO_(4)^(-)`

Answer

C

Explanation

`Ag_(2)CrO_(4) hArr 2Ag^(+)+CrO_(4)^(2-)`
When `[Ag^(+)]=10^(-4)M` and `[CrO_(4)^(2-)]=10^(-2)M`
Ionic product `=(Ag^(+))^(2)xx CrO_(4)^(2-)`
`=((10^(-4))^(2) xx 10^(-2))/(2)=(10^(-10))/(2)`
`=5 xx 10^(-11) gtK_(sp)`