The correct order of decreasing acidic nature of `H_(2)O, ROH, HC -= CH` and `NH_93)` is

Options

A. `HC-=CHgtH_(2)OgtROHgtNH_(3)`
B. `H_(2)OgtROHgtHC-=CHgtNH_(3)`
C. `ROHgtNH_(3)gtHC-=CHgtH_(2)O`
D. `H_(2)OgtROHgtNH_(3)gtHC-=CH`

Answer

B

Explanation

`{:(H_(2)O,ROH,HC-=CH,NH_(3)),(pK_(a)15.7,16-18,26,38):}`
Smaller the `pK_(a)` value, stronger is the acid. Hence decreasing order of acidic nature is
`H_(2)O gt ROH gt HC -= CH gt NH_(3)`