The pH of the solutions produced by mixing equal volumes of `2.0 xx 10^(-3) M HClO_(4)` and `1.0 xx 10^(-2) MKClO_(4)` is

Options

A. 2.7
B. 2.3
C. `3.0`
D. `1.0`

Answer

C

Explanation

`H^(+)` ions obtained only from `HClO_(4)` which ionises completely ( being a strong acid ). Equal volume of `KClO_(4)` solution added reduces `(H^(+))` ions to half `3.0`
`:. |H^(+)|=(2xx10^(-3))/(2)`
Hence `pH =-log (10^(-3))=3.0`