The solubility of `Ca_(3)(PO_(4))_(2)` in water is y moles `//` litre. Its solubility product is

Options

A. `6 y^(2)`
B. `36y^(4)`
C. `64y^(5)`
D. `108 y^(5)`

Answer

D

Explanation

`underset(y " moles")(Ca_(3)(PO_(4))_(2))hArr underset(3y" moles")(3Ca^(2+))+underset(2y " moles")(2PO_(4)^(3-))`
`K_(sp)=|Ca^(2+)|^(3)|PO_(4)^(3-)|^(2)=(3y)^(3)(2y)^(2)=108 y^(5)`