Home
Class 12
CHEMISTRY
Antibonding MO is formed by...

Antibonding MO is formed by

A

Addition of atomic orbitals

B

Subtraction of atomic orbitals

C

Multiplication of atomic orbitals

D

None of these.

Text Solution

Verified by Experts

The correct Answer is:
B

Antibonding MO is formed by subtraction overlap of AO's
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    DINESH PUBLICATION|Exercise Comprehension M.C.Q|24 Videos
  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    DINESH PUBLICATION|Exercise Matrix Match|4 Videos
  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    DINESH PUBLICATION|Exercise Unit Test - 1|20 Videos
  • CARBOXYLIC ACIDS

    DINESH PUBLICATION|Exercise BRAIN STORMING MULTIPLE CHOICE QUESTIONS (MCQS)|13 Videos
  • CHEMICAL KINETICS

    DINESH PUBLICATION|Exercise Additional Numerical Problems For Practice|16 Videos

Similar Questions

Explore conceptually related problems

When two AO s combine energy of bonding MO is lowered by x while of antibonding MO is raised by y Then .

Statement 1: The B.O. of F_(2) molecule is 1. Statement 2: In F_(2) molecule, the number of electrons in the antibonding M.O. is two less than in bonding M.O.

Molecular orbitals are formed by the overlap of atomic orbitals. The combining orbitals must have proper orientation so that they can overlap to a considerable extent. Two atomic orbitals combine to form two molecular orbitals called bonding molecular orbital and antibonding molecular orbital. Bonding molecular orbital is stable and antibonding molecular orbital is unstable. sigma MO is formed by head on overlap while pi MO is formed by sidewise overlap. The MOs are filled with electrons according to the same rules as followed for filling atomic orbitats. Bond order is one of the most important parameter to compare the bond strength and bond length of bonds. Why has N_2 a larger dissociation energy than N_2 ^(+) whereas O_2 has a lower dissociation energy than O_(2)^(+) ?

Out of bonding and antibonding M.O, which is filled first and why?

Statement 1: The addition of electron in antibonding M.O. decreases bond order. Statement 2: Antibonding electrons tend ot bring the atoms close together.

Molecular orbitals are formed by the overlap of atomic orbitals. Two atomic orbitals combine to form two molecular orbitals called bonding and antibonding MO s . The molecular orbitals are filled with electrons following the same rules as followed for filling of atomic orbitals. The molecular orbitals electronic configurations help us to calculate bond order when which give important information about bond strength and bond length. Considering Z - axis as internuclear axis, which one of the following will be for sigma antibonding MO? (i) 2p_(y)+2p_(y)" "2p_(x)-2p_(y) (iii) 2s+2p_(z)" "(iv) 2p_(z)-2p_(z)

Molecular orbitals are formed by the overlap of atomic orbitals. Two atomic orbitals combine to form two molecular orbitals called bonding and antibonding MO s . The molecular orbitals are filled with electrons following the same rules as followed for filling of atomic orbitals. The molecular orbitals electronic configurations help us to calculate bond order when which give important information about bond strength and bond length. Which has smaller bond length No or NO^(+) ?

Molecular orbitals are formed by the overlap of atomic orbitals. Two atomic orbitals combine to form two molecular orbitals called bonding and antibonding MO s . The molecular orbitals are filled with electrons following the same rules as followed for filling of atomic orbitals. The molecular orbitals electronic configurations help us to calculate bond order when which give important information about bond strength and bond length. Why does Be_(2) molecule not exist?

Molecular orbitals are formed by the overlap of atomic orbitals. Two atomic orbitals combine to form two molecular orbitals called bonding and antibonding MO s . The molecular orbitals are filled with electrons following the same rules as followed for filling of atomic orbitals. The molecular orbitals electronic configurations help us to calculate bond order when which give important information about bond strength and bond length. Which out oof O_(2)^(+) and O_(2)^(-) is more stable?