The ion which is not tetrahedral in shape is

Options

A. `BF_4^-`
B. `NH_4^+`
C. `Cu(NH_3)_4^(2+)`
D. `NiCl_4^-`

Answer

C

Explanation

`[Cu(NH_3)_4]^(2+)` is square planar in shape with `Cu^(2+) d sp^2`-hybridised