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The correct order of bond angles (smalle...

The correct order of bond angles (smallest first) in `H_2 S, NH_3, BF_3 and SiH_4` is

A

`H_2S` lt `SiH_4` lt `NH_3` lt `BF_3`

B

`H_2S` lt `NH_3` lt `BF_3` lt `SiH_4`

C

`H_2`lt `NH_3`lt `SiH_4`lt`BF_3`

D

`NH_3` lt `H_2 S` lt `SiH_4` lt `BF_3`

Text Solution

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The correct Answer is:
To determine the correct order of bond angles (from smallest to largest) in the molecules H₂S, NH₃, BF₃, and SiH₄, we will follow these steps: ### Step 1: Identify the central atom and its valence electrons - **H₂S (Hydrogen Sulfide)**: Sulfur (S) is the central atom. It has 6 valence electrons. - **NH₃ (Ammonia)**: Nitrogen (N) is the central atom. It has 5 valence electrons. - **BF₃ (Boron Trifluoride)**: Boron (B) is the central atom. It has 3 valence electrons. - **SiH₄ (Silane)**: Silicon (Si) is the central atom. It has 4 valence electrons. ### Step 2: Calculate the steric number for each molecule The steric number is calculated as the number of valence electrons of the central atom plus the number of monovalent atoms attached to it. - **H₂S**: Steric number = 6 (S) + 2 (H) = 8/2 = 4 - **NH₃**: Steric number = 5 (N) + 3 (H) = 8/2 = 4 - **BF₃**: Steric number = 3 (B) + 3 (F) = 6/2 = 3 - **SiH₄**: Steric number = 4 (Si) + 4 (H) = 8/2 = 4 ### Step 3: Determine the hybridization and molecular geometry - **H₂S**: Steric number 4 → Hybridization: sp³ → Geometry: Tetrahedral (with 2 lone pairs) → Bond angle: ~92° (due to lone pair repulsion) - **NH₃**: Steric number 4 → Hybridization: sp³ → Geometry: Tetrahedral (with 1 lone pair) → Bond angle: ~107° - **BF₃**: Steric number 3 → Hybridization: sp² → Geometry: Trigonal planar → Bond angle: 120° - **SiH₄**: Steric number 4 → Hybridization: sp³ → Geometry: Tetrahedral (no lone pairs) → Bond angle: 109° ### Step 4: Arrange the bond angles in order from smallest to largest Now we can summarize the bond angles: - H₂S: ~92° - NH₃: ~107° - SiH₄: 109° - BF₃: 120° ### Final Order of Bond Angles (Smallest First) The correct order of bond angles from smallest to largest is: 1. H₂S (~92°) 2. NH₃ (~107°) 3. SiH₄ (109°) 4. BF₃ (120°)

To determine the correct order of bond angles (from smallest to largest) in the molecules H₂S, NH₃, BF₃, and SiH₄, we will follow these steps: ### Step 1: Identify the central atom and its valence electrons - **H₂S (Hydrogen Sulfide)**: Sulfur (S) is the central atom. It has 6 valence electrons. - **NH₃ (Ammonia)**: Nitrogen (N) is the central atom. It has 5 valence electrons. - **BF₃ (Boron Trifluoride)**: Boron (B) is the central atom. It has 3 valence electrons. - **SiH₄ (Silane)**: Silicon (Si) is the central atom. It has 4 valence electrons. ...
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The correct order of bond angles among the compounds CH_(4) , NH_(3) and H_(2)O is (A) H_(2)O (B) NH_(3) (C) NH_(3) (D) CH_(4) < H_(2)O < NH_(3)

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Knowledge Check

  • The correct order of bond angles (smallest first) in H_2S, NH_2 ,BF_3 and SiH_4 is

    A
    `H_2S gt N_3 gt SiH_(4) gt BF_3`
    B
    `NH_(3) lt H_2S gt SiH_4 lt BF_3`
    C
    `H_2S lt SiH_4 lt NH_3 lt BF_3`
    D
    `H_2S lt NH_3 lt BF_3 lt SiH_4`
  • The correct order of bond angles (smallest first) in H_2S, NH_2 ,BF_3 and SiH_4 is

    A
    `H_2S gt N_3 gt SiH_(4) gt BF_3`
    B
    `NH_(3) lt H_2S gt SiH_4 lt BF_3`
    C
    `H_2S lt SiH_4 lt NH_3 lt BF_3`
    D
    `H_2S lt NH_3 lt BF_3 lt SiH_4`
  • Which of the following is the correct order of bond angle in H_2S , NH_3 , BF_3 and SiH_4 ?

    A
    `H_2Slt NH_3lt BF_3lt SiH_4`
    B
    `NH_3lt H_2Slt SiH_4lt BF_3`
    C
    ` H_2Slt NH_3lt SiH_4lt BF_3`
    D
    ` H_2Slt SiH_4lt NH_3lt BF_3`
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    The correct order of H-M-H bonds angle is :

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