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If the molecule of HCl were totally pola...

If the molecule of HCl were totally polar, the expected value of dipole moment is 6-12 D (debye) but the experimental value of dipole moment was 1.03 D. Calculate the percentage ionic character.

A

17

B

83

C

50

D

Zero

Text Solution

Verified by Experts

The correct Answer is:
A

Percent ionic character
`=("Obs. dipole moment")/("Cal. dipole moment")xx100`
`=(1.03D)/(6.12D)xx100=17%`
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