Match the compounds in the List with that in List II
`{:("List I","List II"),((a)XeO_3,"1.Planar triangular"),((b)XeOF_4,"2. T-shape"),((c )BO_3^(3-),"3. Trigonal pyramid"),((d)ClF_3,"4. Square pyramid"),((e)I_3^(-)(aq),"5. Linear"),(,"6.Bent"):}`

Options

A. a-1, b-4, c-3, d-2,e-5
B. a -2,b-4, c-1,d-3, e-6
C. a-3, b-4,c-1,d-2,e- 6
D. a-3,b-4, c-1, d-2 , e-5

Explanation

To solve the problem of matching the compounds in List I with those in List II, we need to determine the steric number, hybridization, and molecular shape for each compound in List I. Let's go through each compound step by step.

### Step 1: Analyze each compound in List I

1. **(a) XeO₃**
- **Valence Electrons**: Xenon (Xe) has 8 valence electrons, and there are 3 oxygen atoms (O) contributing 6 electrons (2 each). Total = 8 + 6 = 14.
- **Steric Number**: Steric number = (Valence electrons of central atom + Monovalent atoms attached + Charge) / 2 = (8 + 3 + 0) / 2 = 5.
- **Hybridization**: The hybridization corresponding to a steric number of 5 is sp³d.
- **Shape**: With one lone pair and three bond pairs, the shape is trigonal pyramidal.

2. **(b) XeOF₄**
- **Valence Electrons**: Xe = 8, O = 6, F = 4 * 7 = 28. Total = 8 + 6 + 28 = 42.
- **Steric Number**: Steric number = (8 + 1 + 4) / 2 = 6.
- **Hybridization**: The hybridization for a steric number of 6 is sp³d².
- **Shape**: With one lone pair and four bond pairs, the shape is square pyramidal.

3. **(c) BO₃³⁻**
- **Valence Electrons**: B = 3, O = 3 * 6 = 18. Total = 3 + 18 + 3 (for the charge) = 24.
- **Steric Number**: Steric number = (3 + 0 + 3) / 2 = 3.
- **Hybridization**: The hybridization for a steric number of 3 is sp².
- **Shape**: The shape is trigonal planar.

4. **(d) ClF₃**
- **Valence Electrons**: Cl = 7, F = 3 * 7 = 21. Total = 7 + 21 = 28.
- **Steric Number**: Steric number = (7 + 3 + 0) / 2 = 5.
- **Hybridization**: The hybridization for a steric number of 5 is sp³d.
- **Shape**: With two lone pairs and three bond pairs, the shape is T-shaped.

5. **(e) I₃⁻ (aq)**
- **Valence Electrons**: I = 7 * 3 = 21 + 1 (for the charge) = 22.
- **Steric Number**: Steric number = (7 + 2 + 1) / 2 = 5.
- **Hybridization**: The hybridization for a steric number of 5 is sp³d.
- **Shape**: The shape is linear.

### Step 2: Match the compounds with List II

Now that we have determined the shapes, we can match them with the corresponding options in List II:

- **(a) XeO₃** → **3. Trigonal pyramid**
- **(b) XeOF₄** → **4. Square pyramid**
- **(c) BO₃³⁻** → **1. Planar triangular**
- **(d) ClF₃** → **2. T-shape**
- **(e) I₃⁻ (aq)** → **5. Linear**

### Final Matching

- (a) XeO₃ → 3
- (b) XeOF₄ → 4
- (c) BO₃³⁻ → 1
- (d) ClF₃ → 2
- (e) I₃⁻ (aq) → 5