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The percentage of p character of hybrid ...

The percentage of p character of hybrid orbitals in graphite and diamond are respectively

A

33 and 25

B

50 and 75

C

67 and 75

D

33 and 75

Text Solution

Verified by Experts

The correct Answer is:
C

Hybridization in graphite `sp^2`
% sp character = 2/3 x 100=67 %
Hybridization in diamond =`sp^3`
% p character =`3/4 xx 100=75%`
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Knowledge Check

  • The percentage of p-character of the hybrid orbitals in graphite and diamond are respectively

    A
    33 and 25
    B
    50 and 75
    C
    67 and 75
    D
    33 and 75
  • In graphite and diamond, the percentage of p-characters of the hybrid orbitals in hybridisation are respectively:

    A
    33 and 25
    B
    67 and 75
    C
    50 and 75
    D
    33 and 75
  • In graphite and diamond, the percentage of p-character of the hybird orbitals iin hybridisation are respectively

    A
    33 and 75
    B
    50 and 75
    C
    33 and 25
    D
    67 and 75
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