According to `MOT` whch of the following statement about magnetic character and bond order is corrent regarding `O_(2)^(o+)` .

Options

A. Paramagnetic and Bond order lt `O_2`
B. Paramagnetic and Bond order gt `O_2`
C. Diamagnetic and Bond order lt `O_2`
D. Diamagnetic and Bond order gt `O_2`

Answer

B

Explanation

`O_2`:KK
`(sigma_(2s))^2 (sigma_(2s)^**)^2 (sigma_(2p_z))^2 (sigma_(2p_x))^2 (sigma_(2p_y))^2 (pi_(2p_x)^**)^1 (pi_(2p_y)^**)^1`
B.O.=2
`O^+` :KK
`(sigma_(2s))^2 (sigma_(2s)^**)^2(sigma_(2p_z))^2(pi_(2p_x))^2 (pi_(2p_y)^**) (pi_(2p_x))^1`
B.O.=2.5
Thus `O_2^(+)` is paramagnetic (due to the presence of one unpaired electron in `pi_(2p_x^**`). Its bond order is more than `O_2`.