Home
Class 12
CHEMISTRY
Based on VSEPR theory, the number of 90 ...

Based on VSEPR theory, the number of 90 degree F-B-F angles in `BrF_5` is ……

Text Solution

Verified by Experts

The correct Answer is:
0

Due to repulsion, by lone pairs on the bond pairs, all the four planar bond angle decrease from `90^@` to `84.8^@`.The axial bonds also no longer remains `90^@` FBrF bonds in `BrF_5`
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    DINESH PUBLICATION|Exercise Reason Assertion|37 Videos
  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    DINESH PUBLICATION|Exercise Ultimate Preparatory Package|20 Videos
  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    DINESH PUBLICATION|Exercise Matrix Match|4 Videos
  • CARBOXYLIC ACIDS

    DINESH PUBLICATION|Exercise BRAIN STORMING MULTIPLE CHOICE QUESTIONS (MCQS)|13 Videos
  • CHEMICAL KINETICS

    DINESH PUBLICATION|Exercise Additional Numerical Problems For Practice|16 Videos

Similar Questions

Explore conceptually related problems

Based on VSEPR theory, the number of 90 degree F-Br-F angles in BrF_(5), is

Based on VSEPR theory, the number of 90^(@)F-Br-F angles in BrF_(5) is

Based on VSEPR theory , the number of 90^@ F = Br - F angles in BrR_5 is :

Based on VSEPR theory the number of 90^(@) F -Br -F angles in a molecules of BrF_(5) is_____.

ICI_3 is an orange colored solid that dimerizes in solid state as I_2Cl_6 Based on VSEPR theory , number of 90 degree Cl-l-Cl bond angles is …….. In the dimeric species.

Using VSEPR theory, draw the shape of PCL_(5) and BrF_(4) .

Using VSEPR theory draw the shape of PCI_(5) and BrF_(5) ?.