The dye acriflavine when dissolved in water has its maximum light absorption at 4530 Ã… and has maximum fluorescence emission at 5080 Ã…. The number of fluorescence quantum is, on the average, 53% of the number of quanta absorbed. What percentage of absorbed light energy is emitted as fluorescence?

Options

A. `41%`
B. `47%`
C. `74%`
D. `63%`

Answer

B

Explanation

Energy of each photon absorbed
`E=hv=(hv)/lambda`
`E=(6.63xx10^(-34)Js xx 3 xx 10^8 m//s)/(4530xx10^(-10)m)`
`=4.39xx10^(-19)` J
Energy of each photon emitted E=hv=`(hv)/lambda`
`=(6.63xx10^(-34)Js xx 3 xx 10^8 m//s)/(5080xx10^(-10)m)`
`=3.92xx10^(-19)` J
Energy fraction emitted
`=(0.53(3.92xx10^(-19)))/(4.39xx10^(-19))xx100=47%`