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The increasing order (lowest first) for the values of `e//m` (charge//mass) for electron `(e)`, proton `(p)`, neutron `(n)`, and alpha particle `(alpha)` is

A

n,`alpha`,p,e

B

e,p,n,`alpha`

C

n,p,e,`alpha`

D

n,p,`alpha`,e

Text Solution

Verified by Experts

The correct Answer is:
A

(i)e/m for neutron =`0/2`=0
(ii)e/m for `alpha` particle =`2/4` =0.5
(iii)e/m for proton =`1/1`=1
(iv)e/m for electron =`1/(1//1837)=1837`
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