Which reaction willl not yield alkane?

Options

A. Reduction of acetone with `Mg//H_(2)O`
B. Hydrogenation of ethene
C. Treatment of ethanol with methyl magnesium bromide
D. Soda lime decarboxylation of sodium propionate

Answer

A

Explanation

The reaction give Pinacol (a diol) `CH_(2)-underset(O)underset(||)overset(CH_(3))overset(|)(C)+underset(O)underset(||)overset(CH_(3))overset(|)(C)-CH_(3) underset(H_(2)O)overset(Mg//Hg)to`
`underset("Pinacol")(CH_(3)-underset(OH)underset(||)overset(CH_(3))overset(|)(C)-underset(OH)underset(||)overset(CH_(3))overset(|)(C)-CH_(3))`