How many isomeric compounds are possible for `C_(2)H_(2)Br_(2)` ?

Options

A. 2
B. 3
C. 4
D. 5

Explanation

To determine the number of isomeric compounds possible for the molecular formula \( C_2H_2Br_2 \), we can follow these steps:

### Step 1: Identify the Structure
The molecular formula \( C_2H_2Br_2 \) indicates that we have two carbon atoms, two hydrogen atoms, and two bromine atoms. The structure can be based on the arrangement of these atoms.

### Step 2: Consider Possible Structures
1. **Double Bond Structure**:
- The first possibility is to have a double bond between the two carbon atoms. This can lead to different arrangements of the bromine and hydrogen atoms.
- **Trans Isomer**: One bromine atom on each carbon, opposite to each other.
- **Cis Isomer**: Both bromine atoms on the same side of the double bond.

2. **Single Bond Structure**:
- The second possibility is to have a single bond between the two carbon atoms. In this case, both bromine atoms can be on the same carbon or distributed between the two carbons.
- **1,1-Dibromoethane**: Both bromine atoms attached to the first carbon (C1).
- **1,2-Dibromoethane**: One bromine atom on each carbon (C1 and C2).

### Step 3: Count the Isomers
From the above considerations, we can summarize the isomers:
1. **Cis-1,2-Dibromoethene** (Cis configuration)
2. **Trans-1,2-Dibromoethene** (Trans configuration)
3. **1,1-Dibromoethane** (Both Br on the same carbon)
4. **1,2-Dibromoethane** (One Br on each carbon)

### Conclusion
Thus, the total number of isomeric compounds possible for \( C_2H_2Br_2 \) is **4**.