Reaction of benzonitrile with methyl magnesium iodide followed by hydrolysis gives :

Options

A. toluene
B. acetophenone
C. Benzoic acid
D. iodobenzene

Explanation

To solve the problem of the reaction of benzonitrile with methyl magnesium iodide followed by hydrolysis, we can break down the steps as follows:

### Step 1: Identify the Reactants
- **Benzonitrile**: This is an aromatic compound with the formula C6H5CN, which consists of a benzene ring attached to a nitrile group (C≡N).
- **Methyl Magnesium Iodide (CH3MgI)**: This is a Grignard reagent, which is a strong nucleophile.

### Step 2: Reaction of Benzonitrile with Methyl Magnesium Iodide
- When benzonitrile reacts with methyl magnesium iodide, the nucleophilic methyl group (CH3-) from the Grignard reagent attacks the electrophilic carbon of the nitrile group (C≡N).
- This results in the formation of an intermediate compound, which is a ketimine.

### Step 3: Hydrolysis of the Intermediate
- The intermediate ketimine formed from the reaction is then subjected to hydrolysis. Hydrolysis involves the addition of water (H2O) in the presence of an acid (often H3O+).
- During hydrolysis, the ketimine is converted into a ketone.

### Step 4: Identify the Final Product
- The final product after hydrolysis is **Acetophenone**, which has the structure C6H5C(O)CH3. It is a ketone with a phenyl group (C6H5) and an acetyl group (C(O)CH3).

### Conclusion
- Therefore, the reaction of benzonitrile with methyl magnesium iodide followed by hydrolysis gives **Acetophenone**.

### Final Answer
The product formed is **Acetophenone (C6H5C(O)CH3)**.

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