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Which one of the following is least basi...

Which one of the following is least basic ?

A

Aniline

B

Diethylamine

C

`p-`sulphanilic acid

D

`o-`nitroaniline

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The correct Answer is:
To determine which compound is the least basic among the given options, we need to analyze the basicity of each compound based on the presence of electron-donating or electron-withdrawing groups and the availability of the lone pair of electrons on the nitrogen atom. ### Step-by-Step Solution: 1. **Identify the Compounds**: - **Aniline**: C6H5NH2 - **Diethylamine**: (C2H5)2NH - **Para-sulfonylic acid**: C6H4(NH2)SO3H (4-amino-benzene-sulfonylic acid) - **Ortho-nitro-aniline**: C6H4(NH2)(NO2) (where NO2 is at the ortho position) 2. **Analyze Basicity**: - Basicity is influenced by the availability of the lone pair of electrons on the nitrogen atom. The more available the lone pair, the stronger the base. - Electron-donating groups (like alkyl groups) increase basicity, while electron-withdrawing groups (like nitro and sulfonyl groups) decrease basicity. 3. **Evaluate Each Compound**: - **Aniline**: The lone pair on nitrogen is available for donation, making it a weak base. - **Diethylamine**: The two ethyl groups are electron-donating, increasing the availability of the lone pair, making it a stronger base than aniline. - **Para-sulfonylic acid**: The sulfonyl group (SO3H) is electron-withdrawing, which decreases the availability of the lone pair on nitrogen, but it is still more available than in ortho-nitro-aniline. - **Ortho-nitro-aniline**: The nitro group (NO2) is a strong electron-withdrawing group, especially at the ortho position, which significantly reduces the availability of the lone pair on nitrogen due to resonance and inductive effects. 4. **Conclusion**: - Among the four compounds, ortho-nitro-aniline has the least availability of the lone pair on nitrogen due to the strong electron-withdrawing effect of the nitro group at the ortho position. - Therefore, **the least basic compound is ortho-nitro-aniline**. ### Final Answer: **Ortho-nitro-aniline is the least basic compound among the given options.**

To determine which compound is the least basic among the given options, we need to analyze the basicity of each compound based on the presence of electron-donating or electron-withdrawing groups and the availability of the lone pair of electrons on the nitrogen atom. ### Step-by-Step Solution: 1. **Identify the Compounds**: - **Aniline**: C6H5NH2 - **Diethylamine**: (C2H5)2NH - **Para-sulfonylic acid**: C6H4(NH2)SO3H (4-amino-benzene-sulfonylic acid) ...
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DINESH PUBLICATION-CYANIDES, ISOCYANIDES, NITROCOMPOUNDS AND AMINES-Unit test - 8
  1. Which one of the following is least basic ?

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  2. Select incorrect statement

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  3. H(2)O is reduce with Sn//HCl. Product formed

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  4. RNH(2) can be converted into R, NH and no other amine by

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  5. Which is general order of basicity for water and amines

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  6. Consider following hydrogen-bonded amines I and II Select the cor...

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  7. Which is the strongest conjugate acid ?

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  8. When (CH(3))(3)CNH(3)^(+)Cl^(-) is heated, product is

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  9. Select correct statement (s), about the following reaction [(CH(3))(3)...

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  10. Major alkene of the following reaction is {:(CH(3)-C CH(2)CH(3)),(" ...

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  11. Exhaustive methylation of CH(3)CH(2)NH(2) forms

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  12. Following 2^(@) amine has chiral carbon as indicated H-underset(CH(3))...

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  13. Major product of the following reaction is {:(" "NH(...

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  14. Consider the following reaction underset((A))(CH(3)CONH(2)) overset(...

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  15. Which is soluble in NONO(2) and dil HCl mixture forming salt ?

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  16. Tertiary amine is oxidized to oxide by

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  17. Cope elimination is an intramolecular, E(2) reaction because

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  18. Cope elimination

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  19. In gas phase, the basicities of amines increase in the order NH(3) lt ...

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  20. In aqueous phase basicity of amines is in order NH(3) lt (CH(3))(3)N...

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  21. Which of the following chemicals are used to manufacture methyl isocya...

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