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The compound that will react most readil...

The compound that will react most readily NaOH to form methanol is

A

`(CH_(3))_(4)N^(+)I^(-)`

B

`CH_(3)OCH_(3)`

C

`(CH_(3))_(3)S^(+) I^(-)`

D

`(CH_(3))_(3)C Cl`.

Text Solution

Verified by Experts

The correct Answer is:
A
`(CH_(3))_(4) overset(+)(N)I^(-)+NaOH rarr NaI+(CH_(3))_(3)N+CH_(3)OH`
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