The reaction of NaCl and `K_2Cr_2O_7` with conc. `H_2SO_4` results in the formation of

Options

A. `CrO_2Cl_2`
B. `CrOCl_2`
C. `CrO_2Cl`
D. `CrOCl_3`

Explanation

To solve the question regarding the reaction of NaCl and K2Cr2O7 with concentrated H2SO4, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in the reaction are:
- Sodium Chloride (NaCl)
- Potassium Dichromate (K2Cr2O7)
- Concentrated Sulfuric Acid (H2SO4)

### Step 2: Write the Balanced Chemical Equation
When NaCl and K2Cr2O7 react with concentrated H2SO4, the balanced chemical equation can be written as follows:

\[ 6 \text{NaCl} + \text{K}_2\text{Cr}_2\text{O}_7 + 6 \text{H}_2\text{SO}_4 \rightarrow 2 \text{CrO}_2\text{Cl}_2 + 2 \text{KHSO}_4 + 2 \text{NaHSO}_4 + 2 \text{H}_2\text{O} \]

### Step 3: Identify the Products
From the balanced equation, we can identify the products formed:
- Chromyl Chloride (CrO2Cl2)
- Potassium Bisulfate (KHSO4)
- Sodium Bisulfate (NaHSO4)
- Water (H2O)

### Step 4: Determine the Main Product
Among the products formed, the main product of interest is Chromyl Chloride, which is represented by the formula CrO2Cl2.

### Step 5: Choose the Correct Option
From the options provided:
1. CrO2Cl2 (Chromyl Chloride)
2. CrOCl2
3. CrO2Cl
4. CrOCl3

The correct answer is **Option 1: CrO2Cl2**.

### Summary of the Reaction
The reaction of NaCl and K2Cr2O7 with concentrated H2SO4 results in the formation of Chromyl Chloride (CrO2Cl2) along with potassium bisulfate, sodium bisulfate, and water.

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