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When SO2 is passed through acidified K2C...

When `SO_2` is passed through acidified `K_2Cr_2O_7` solution

A

The solution is turned blue

B

The solution is decolourised

C

`SO_2` is reduced

D

Green `Cr_2(SO_4)_3` is formed

Text Solution

Verified by Experts

The correct Answer is:
D
`K_2Cr_2O_7 +3SO_2+H_2SO_4 to K_2SO_4 + Cr_2(SO_4)_3 + H_2O + SO_2`
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