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Following data is given for the reaction...

Following data is given for the reaction : `CaCO_3(s)hArrCaO(s)+CO_2(g)`
`Delta_(f)H^(Theta)[CaO(s)]=-635.1kJ mol^(-1)`
`Delta_(f)H^(Theta)[Ca_2(s)]=-393.5kJ mol^(-1)`
`Delta_(f)H^(Theta)[CaCO_3(s)]=-1206.9kJ mol^(-1)`
Predict the effect of temperature on the equilibrium of the above reaction.

Text Solution

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`Delta_(f)h^(Theta)=SigmaDelta_fH_("products")^(Theta)-SigmaDelta_(f)H_("reactants")^(Theta)`
`=[Delta_fH^(Theta)CaO(s)+Delta_fH^(Theta)CO_(2)(g)]-[Delta_fH^(Theta)CaCO_(3)(s)]`
`=178.3kJ " mol"^(-1)`.
The forward reaction is of endothermic nautre. This means that when temperature is increased, according to Le Chatelier's principle, the reaction will proceed in the forward dirction.
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