HCI is a stronger acid then `CH_(3)COOH` but both have almost same acidic strength when dissolved in liquid ammonia. Explain.

Explanation

`underset("Acid-I")(HCl) + underset("Base-I")(NH_(3)) ("Liqud") hArr underset("Base-I")Cl^(+) + underset("Acid-II")(NH_(4)^(+))`
`underset("Acid-I")(CH_(3)COOH) + underset("BaseI")(NH_(3)) ("Liqud") hArr underset("Base-I")(CH_(3)COO^(-)) + underset("Acid-II")(NH_(4)^(+))`
Liquid ammonia is such a strong base that even `CH_(3)CPOOH` which is otherwise a weak acid gets almost completely dissociated in it. It therefore behaves as a strong acid just like HCI.