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Find the value of equilibrium constant i...

Find the value of equilibrium constant if the rate constante for the forward and backward reactions are , `2.38 xx 10^(-4) " and " 8.15 xx 10^(-4)` respetively.

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`K_(c) =(K_(f))/(k_(b)) =(2.38 xx 10^(-4))/(8.15 xx 10^(-4)) =0.29`
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