The density `("in g mL"^(-1))` of a 3.60 M sulphuric acid solution that is 29 % of acid by mass is : (Given molar mass `= 98 g mol^(-1)`)

Options

A. 1.45
B. 1.64
C. 1.88
D. 1.22

Answer

D

Explanation

By definition, `3.6 M(3.6xx98=352.8g)` of `H_(2)SO_(4)` are present in 1000 mL of the solution
29.0 g of acid are present in solution = 100 g
352.8 g of acid are present in solution
`= ((100g)xx(352.8g))/((29g))`
Density of solution `=("Mass of solution")/("Volume of solution")`
`= ((1216g))/((1000mL))=1.22"g mL"^(-1)`.