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The density of 3 M solution of NaCl is 1...

The density of 3 M solution of NaCl is `1.25 "g L"^(-1)`. The molality of the solution is :

A

2.79

B

1.79

C

0.79

D

2.98 M

Text Solution

Verified by Experts

The correct Answer is:
A
Density (d) `= ("Mass of solution")/("Volume of solution")`
Mass of solution `= (1.25 gL^(-1)) xx(1000 mL) = 1250 g`
Mass of solvent = Mass of solution - Mass of solute
`= (1250 - 3 xx 58.5) = 1074.30 g`
Molality of solution `= ("No. of moles of solute")/("Mass of solvent in kg")=(("3 mol"))/(("1.074 kg"))`
`=2.79"mol kg"^(-1)=2.79` m.
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Knowledge Check

  • The density of 3M solution of NaCl is 1.25 g mL^(-1) . The molality of the solution is

    A
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