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When metal X is treated with sodium hydr...

When metal X is treated with sodium hydroxide, a white precipitate (A) is obtained, which is soluble in excess of NaOH to give soluble complex (B). Compound (A) is soluble in dilute HCl to form compound (C). The compound (A) when heated strongly gives (D), which is used to extract metal. Identify (X), (A), (B), (C) and (D). Write suitable equations to support their identities.

Text Solution

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The data duggests that the metal 'X' aluminium. The reactions in which aluminium participates leading to the formation of compounds (A),(B),© and (D) are given:
(i) Aluminium (X) reacts with NaOH upon heating to form a whie precipitate of `Al(OH)_(3)` i.e., compound (A) which dissolves in excess of NaOH to form soluble complex 'B'
`Al(OH)_(3)+2NaOH(aq)rarr2Na^(+)[Al(OH)_(4)]^(-)`
Soluble complex
(ii) The compound (A) dissolves in dil HCl to form aluminium chloride (C)
`Al(OH)_(3)+3HCl(aq)rarrAlCl_(3)(aq)+3H_(2)O(aq)`
(iii) Upon heating `Al(OH)_(3)` is converted into alumina (D)
`2Al(OH)_(3)overset("Heat")rarrAl_(2)O_(3)(s)+3H_(2)O(l)`
`Al_(2)O_(3)` is used in the extraction of the Al metal.
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