When `BCl_(3)` is treated with water, it hydrolyses and forms `[B(OH)_(4)]^(-)` only whereas `AlCl_(3)` in acidified aqueous solution forms `[Al(H_(2)O)_(6)]^(3+)` ion, Explain what is the hybridisation of boron and aluminium in these species?

Explanation

`BCl_(3)` when hydrolysed wth water forms `[B(OH)_(4)]^(-)` ion, in this ion, boron atom is `sp^(3)` hybridised and the shape of the ion is tetrahedral when `AlCl_(3)` is hydrolysed with water in the presense of an acid `[Al(H_(2)O_(6))]^(3+)` ion is formed. in this, alumm um atoms is `sp^(2)d^(2)` hybridised and the shape of the complex ion is octahedral.