Home
Class 12
CHEMISTRY
Consult the table of standard electrode ...

Consult the table of standard electrode potential and suggest three substances that can oxidize `Fe^(2+)` ions under suitable conditions.

Text Solution

Verified by Experts

The oxidation of `Fe^(2+)` ions proceeds as follows :
`Fe^(2+)toFe^(3+)+e^(-) ,E_(OX)^(@)=-0.77 V`
Only those substance can oxidise `Fe^(2+)` ions to `Fe^(3+)` ions which can accept electrons released during oxidation or are placed above iron in electrochemical series. These are : `Cl_(2)(g),Br_(2)(g) " and " Cr_(2)O_(7)^(2-) "ions " ("in the acidic medium")`.
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    DINESH PUBLICATION|Exercise N.C.E.R.T. EXERCISE|18 Videos
  • ELECTROCHEMISTRY

    DINESH PUBLICATION|Exercise Short Answer Type Questions|22 Videos
  • ELECTROCHEMISTRY

    DINESH PUBLICATION|Exercise Example|74 Videos
  • D-AND -F BLOCK ELEMENTS

    DINESH PUBLICATION|Exercise BRAIN STORMING MULTIPLE CHOICE QUESTIONS (MCQS)|13 Videos
  • ETHERS

    DINESH PUBLICATION|Exercise (MCQs)|8 Videos

Similar Questions

Explore conceptually related problems

The positive value of the standard electrode potential of Cu^(2+)//Cu indicates that.......

On the basis of standard electrode potential values, suggest which of the following reactions would take place? (Consult the book for E^(ϴ) value) (a) Cu+Zn^(2+)toCu^(2+)+Zn (b) Mg+Fe^(2+)toMg^(2+)+Fe (c ) Br_(2)+2Cl^(-)toCl_(2)+2Br^(-) (d) Fe+Cd^(2)toCd+Fe^(2+)

Calculating the emf from standard potentials: A galvanic cell consists of an Al electrode in a 1.0M Al(NO_(3))_(3) solution and an Fe electrode in a 1.0M Fe(NO_(3))_(2) solution. Calculate the standard emf of this electrohemical cell at 25^(@)C . Also write the cell reaction. Strategy: From the table of standard electrode potentials, write the two reduction half reaction and standard electrode potentials for the cell. Change the direction of the half-cell reaction corresponding tol the smaller (or more negative) electrode potential. Multiply the when the half-reactions are added the electrons cancel. The sum of the half-reactions is the cell reaction. Add the electrode potentials to get the cell emf.