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The molar conductivity of 0.025 M methan...

The molar conductivity of 0.025 M methanoic acid (HCOOH) is `46.15" S "cm^(2)mol^(-1)`. Calculate its degree of dissociation and dissociation constant. Given `lambda_((H^(+)))^(@)=349.6" S "cm^(2)mol^(-1)` and `lambda_((HCOO^(-)))^(@)=54.6" S " cm^(2)mol^(-1)`.

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For answer, consulat example 69, on Kohlrausch's Law.
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The molar conductivity of 0.25 mol L^(-1) methanoic acid is 46.1 S cm^(2) mol^(-1) . Calculate the degree of dissociation constant. Given : lambda_((H^(o+)))^(@)=349.6S cm^(2)mol^(-1) and lambda_((CHM_(3)COO^(c-)))^(@)=54.6Scm^(2)mol^(-1)

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