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What does the negative sign in the expre...

What does the negative sign in the expression `E_(Zn^(2+)//Zn)^(@)=-0.76V` mean?

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It implies that Zn is more reactive than hydrogen or it is a stronger reducing agent.In a cell containing zinc electrode and standard hydrogen electrode present in two half cells, zinc will be oxidised to `Zn^(2+)` ions while `H^(+)` ions will get reduced to hydrogen.
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Can a solution of 1 M ZnSO_(4) be stored in a vessel made of copper ? Given that E_(Zn^(+2)//Zn)^(@) =-0.76V and E_(Cu^(+2)//Cu)^(@)=0.34 V

For a standard cell Zn(s)|Zn^(2+)(1 M)||Cu^(2+)(1 M)|Cu(s) Write the electrode reaction and cell reaction. Also find the e.m.f. of cell if ? E_(Zn^(2+)|Zn)^(@)=-0.76" V", E_(Cu^(2+)|Cu)^(@)=+0.34" V" .

For the galvanic cell Zn(s)[Zn^2+ (aq)||Ag^+(aq) Ag(s)] , G° of the reaction in joule will be E°_ (Zn^(2+)) /( Zn )= - 0.76V , E°_( Ag_+)/(Ag )= 0.80 V

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