Consider a cell given below.
`Cu|Cu^(2+)|Cl^(-)|Cl_(2).Pt`
Write the reactions that occur at anode and cathode.

Explanation

The reaction taking place at the two electrodes are :
At anode : `Cu(s) to Cu^(2+)(aq) +2e^(-)`
At cathode : `Cl_(2)(g) +2e^(-) to 2Cl^(-)(aq)` Thus,Cu(s) is oxidised to `Cu^(2+)`(aq) ions at anode while `Cl_(2)`(g) is reduced to `Cl^(-)` (aq) ions at cathode.