Two platinum electrides are dipped in an aqueous solution of copper sulphate blue in colour. A current is passed through it.
(a) What will happen on the two electrodes ?
(b) What will happen to the colour of the solution ?
(c ) Predict the nature of the solution left in the electrolytic cell.

Explanation

(a) Copper will be deposited on the cathode i.e., the electrode connected to the negative terminal. Oxygen gas `(O_(2))` will evolve at the anode.
(b) The blue colour of the solution will slowly disappear and it will become colourless.
(c ) The solution left in the electrolytic cell will be acidic (aqueous solution of `H_(2)SO_(4)`). For details, consult text part.