The reduction potentials of `Cu^(2+)//Cu` and `Ag^(+)//Ag` electrodes are 0.34V and 0.80 v respectively. For what concentration of `Ag^(+)` ions will the EMF of the cell at `25^(@)C` is zero ? Given that the concentration of `Cu^(2+)` is 0.01 M.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Write the half-reactions and identify the anode and cathode
The half-reactions for the given electrodes are:
- For copper: \( Cu^{2+} + 2e^- \rightarrow Cu \) (Reduction potential = 0.34 V)
- For silver: \( Ag^+ + e^- \rightarrow Ag \) (Reduction potential = 0.80 V)

Since the reduction potential of silver is higher than that of copper, silver will act as the cathode and copper will act as the anode.
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