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What is the volume of O(20 liberated at ...

What is the volume of `O_(20` liberated at anode at `STP` in the electrolysis of `CdSO_(4)` solution when a current of `2 A` is passed for `8 m i n ?`

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The correct Answer is:
55.7 cc at N.T.P.
The oxidation reaction at anode is :
`2H_(2)O(l) to 4H^(+)(aq)+underset(22400 c"c")(O_(2)(g))+underset((4 Faradays))underset(4 mol)(4e^(-))`
Quantity of charge passed(Q)`="Current in amperes"xx"time4 in seconds"`
`=( 2amp)xx(8xx60 s)=960 C`
`4xx96500 C` of charge evolve oxygen at anode`=22400 "c"c`
960 C of charge evolve oxygen at anode`=(22400 "c"c)/((4xx96500C))xx(960C)=55.7"c"c`.
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