How many electrons flow when a current of 5 amperes is passed through a solution for 193 seconds ?

Answer

`6.022xx10^(21)`

Explanation

3 Faraday of charge will evolve`Cl_(2)` (g)=33.6L
Quantity of charge passed (Q)`=(5 amp)xx(193 s)=965 C`
By passing 96500 C (1F) of charge, the electrons flowing `=6.022xx10^(23)`
By passing 965 C of charge, the electrons flowing `=(6.022xx10^(23))/((96500C))xx(965C)=6.022xx10^(21)`