The rate constant for a first order reaction is `60s^(-1)`. How much time would it take to reduce 1g of the reactant to `0.0625` g

Explanation

For first order reaction,
`k=2.303/t log (a)/(a-x)` or `t=(2.303)/t log a/(a-x)= (2.303)/(60s^(-1)log 1/(0.0625))`
`t=(2.303)/(60s^(-1)) log (16)=(2.303 xx 1.2041)/(60s^(-1)) = 0.0462 s`