Home
Class 12
CHEMISTRY
What is the change in oxidation state of...

What is the change in oxidation state of Cr" in "`K_(2)Cr_(2)O_(7)` when it acts as an oxidising agent.

Text Solution

Verified by Experts

The correct Answer is:
3
`overset(+6)((Cr_(2)O_(7))^(2-))=overset(+3)(2(Cr)^(3+))`
Change in oxidation state +6 to +3 =3
Promotional Banner

Topper's Solved these Questions

  • D-AND -F BLOCK ELEMENTS

    DINESH PUBLICATION|Exercise BRAIN STORMING MULTIPLE CHOICE QUESTIONS (MCQS)|13 Videos

  • D-AND -F BLOCK ELEMENTS

    DINESH PUBLICATION|Exercise ASSERTION-REASON TYPE QUESTIONS|23 Videos

  • CYANIDES, ISOCYANIDES, NITROCOMPOUNDS AND AMINES

    DINESH PUBLICATION|Exercise Unit test - 8|20 Videos

  • ELECTROCHEMISTRY

    DINESH PUBLICATION|Exercise ADDITIONAL NUMERICAL PROBLEMS FOR PRACTICE|12 Videos

Similar Questions

Explore conceptually related problems

The oxidation state of Cr in K_(2)Cr_(2)O_(7) is:

The oxidation number of Cr in K_(2)Cr_(2)O_(7) is

The oxidation state of Cr in Cr_(2)O_(7)^(2-) is

The oxidation state of Cr in K _ 2 Cr _ 2 O _ 7 is

Write oxidation number of Cr in Cr_(2)O_(7)^(2–) .