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The number of moles of acidified KMn0(4)...

The number of moles of acidified `KMn0_(4)` required to convert one mole of sulphite ion into sulphate ion is, x/y. The value of X + y = 0 is

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The correct Answer is:
7
`{:(2MnO_(4)^(-)+6H^(+)+5SO_(3)^(2-)),(" 2 mole 5 moles"),(" "darr),(2Mn^(2+)+5SO_(4)^(2-)+3H_(2)O):}`
5 moles of `SO_(3)^(2-)-= `2 moles of `MnO_(4)^(-)`
1 mole of `SO_(3)^(2-)-=2//5` moles of `MnO_(4)^(-)`
THerefore, `(x)/(y)=(2)/(5)`
or x+y=2+5=7.
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