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When 0.1 mol CoCl(3)(NH(3))(5) is treate...

When 0.1 mol `CoCl_(3)(NH_(3))_(5)` is treated with excess of `AgNO_(3)`, 0.2 mole of AgCl are obtained. The conductivity of solution will correspond to

A

`1:3` electrolyte

B

`1:2` electrolyte

C

`1:1` electrolyte

D

`3:1` electrolyte

Text Solution

Verified by Experts

The correct Answer is:
B
The structure of complex is `[Co(NH_(3))_(5)Cl]Cl_(2)`. The conductivity of the solution will correspond to `1:2` electrolyte.
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