The perpendicular form of the line `3x+4y-5=0` is

Options

A. `x cos alpha+y sin alpha=1 ` where `cos alpha =3//5, sin alpha=4//5`
B. `xcos alpha-y sin alpha=1` where `cos alpha=3//5, sin alpha = 4//5`
C. `x cos alpha+y sin alpha=1` where `cos alpha=4//5, sin alpha=3//5`
D. `x cos alpha-y sin alpha=1 ` where ` cos alpha =4//5, sin alpha=3//5`

Answer

1